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Sort so folders are grouped together
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@ -118,7 +118,7 @@ class GalleryApp(App[None]):
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# Well, I can do it mostly, but for comparing "v1" and "v1.1", I need to consider the version number as a group.
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# For two-number version strings, I could consider it as a float, but for three-number version strings, a tuple should work.
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# I don't have any three-number version strings in the filenames of my ANSI art samples, but TODO: generalize this.
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matches_and_paths = [(re.findall(r"(\d*(?:\.\d+)?)(\D*)", path.name), path) for path in paths]
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matches_and_paths = [(re.findall(r"(\d*(?:\.\d+)?)(\D*)", str(path)), path) for path in paths]
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sorted_parts_and_paths = sorted(matches_and_paths, key=lambda matches_and_path: [
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[
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# If ints or strings are conditionally omitted, it leads to int vs str comparison errors.
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