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Simplify a test for mempool manager's new_peak (#16796)
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@ -1341,10 +1341,12 @@ def test_dedup_info_eligible_3rd_time_another_2nd_time_and_one_non_eligible() ->
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@pytest.mark.anyio
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@pytest.mark.parametrize("new_height_step", [1, 2, -1])
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async def test_coin_spending_different_ways_then_finding_it_spent_in_new_peak(new_height_step: int) -> None:
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# This test makes sure all mempool items that spend a coin (in different ways)
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# that shows up as spent in a block, get removed properly.
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# NOTE: this test's parameter allows us to cover both the optimized and
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# the reorg code paths
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"""
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This test makes sure all mempool items that spend a coin (in different ways)
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that shows up as spent in a block, get removed properly.
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NOTE: `new_height_step` parameter allows us to cover both the optimized and
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the reorg code paths
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"""
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new_height = uint32(TEST_HEIGHT + new_height_step)
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coin = Coin(IDENTITY_PUZZLE_HASH, IDENTITY_PUZZLE_HASH, 100)
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coin_id = coin.name()
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@ -1367,9 +1369,7 @@ async def test_coin_spending_different_ways_then_finding_it_spent_in_new_peak(ne
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# Mark this coin as spent
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test_coin_records = {coin_id: CoinRecord(coin, uint32(0), TEST_HEIGHT, False, uint64(0))}
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block_record = create_test_block_record(height=new_height)
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npc_result = NPCResult(None, make_test_conds(spend_ids=[coin_id]), uint64(0))
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assert npc_result.conds is not None
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await mempool_manager.new_peak(block_record, [bytes32(s.coin_id) for s in npc_result.conds.spends])
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await mempool_manager.new_peak(block_record, [coin_id])
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# As the coin was a spend in all the mempool items we had, nothing should be left now
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assert len(mempool_manager.mempool.get_items_by_coin_id(coin_id)) == 0
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assert mempool_manager.mempool.size() == 0
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