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4 lines
159 B
Plaintext
4 lines
159 B
Plaintext
let ashr x y = if head x then ~ (~ x >> y) else x >> y
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:exhaust \(x : [8]) (y : [8]) -> x >>$ y == ashr x y
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:prove \(x : [8]) (y : [8]) -> x >>$ y == ashr x y
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