1myid : (a : Type) -> a -> a
4idid : (a : Type) -> a -> a
7app : (a -> b) -> a -> b
10foo : a -> b -> c -> d -> e -> e
14doapp x = app (myid _) x
18id : (b : Type k) -> b -> b : Type l, k < l
20foo = id ((a : Type k) -> a -> a) id
23So we have k < m, k < l, m <= k
25 when converting Type m against Type n, we must have m <= n
26 if we can reach m from n, we have an inconsistency
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