1proof011.idr:20:5-21:18:
2When checking right hand side of vassoc' with expected type
3 (x :: xs) ++ ys ++ zs = ((x :: xs) ++ ys) ++ zs
5rewriting xs ++ ys ++ xs to (xs ++ ys) ++ xs did not change type x ::
12When checking right hand side of vassoc' with expected type
13 (x :: xs) ++ ys ++ zs = ((x :: xs) ++ ys) ++ zs
15rewriting xs ++ ys ++ xs to (xs ++ ys) ++ xs did not change type x ::
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