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3f3f45580a
Each of these strings would previously rely on StringView's char const* constructor overload, which would call __builtin_strlen on the string. Since we now have operator ""sv, we can replace these with much simpler versions. This opens the door to being able to remove StringView(char const*). No functional changes.
68 lines
2.1 KiB
C++
68 lines
2.1 KiB
C++
/*
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* Copyright (c) 2020, the SerenityOS developers.
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*
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* SPDX-License-Identifier: BSD-2-Clause
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*/
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#include <LibTest/TestCase.h>
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#include <AK/StringView.h>
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#include <AK/Trie.h>
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TEST_CASE(normal_behavior)
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{
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Trie<char, String> dictionary('/', "");
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constexpr StringView data[] { "test"sv, "example"sv, "foo"sv, "foobar"sv };
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constexpr size_t total_chars = 18; // root (1), 'test' (4), 'example' (7), 'foo' (3), 'foobar' (3, "foo" already stored).
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for (auto& view : data) {
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auto it = view.begin();
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MUST(dictionary.insert(it, view.end(), view, [](auto& parent, auto& it) -> Optional<String> { return String::formatted("{}{}", parent.metadata_value(), *it); }));
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}
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size_t i = 0;
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MUST(dictionary.for_each_node_in_tree_order([&](auto&) {
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++i;
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}));
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EXPECT_EQ(i, total_chars);
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for (auto& view : data) {
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auto it = view.begin();
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auto& node = dictionary.traverse_until_last_accessible_node(it, view.end());
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EXPECT(it.is_end());
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EXPECT(node.metadata().has_value());
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EXPECT_EQ(view, node.metadata_value());
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}
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constexpr StringView test_data_with_prefix_in_dict[] { "testx"sv, "exampley"sv, "fooa"sv, "foobarb"sv, "fox"sv, "text"sv };
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for (auto& view : test_data_with_prefix_in_dict) {
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auto it = view.begin();
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auto& node = dictionary.traverse_until_last_accessible_node(it, view.end());
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EXPECT(!it.is_end());
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EXPECT(node.metadata().has_value());
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EXPECT(view.starts_with(node.metadata_value()));
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}
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}
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TEST_CASE(iterate)
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{
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Trie<int> bunch_of_numbers { 0 };
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Array<int, 64> input;
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for (size_t i = 0; i < input.size(); ++i)
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input[i] = i;
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MUST(bunch_of_numbers.insert(input.begin(), input.end()));
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// Iteration order is preorder (order between adjacent nodes is not defined, but parents come before children)
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// in this case, the tree is linear.
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size_t i = 0;
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bool is_root = true;
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MUST(bunch_of_numbers.for_each_node_in_tree_order([&](auto& node) {
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if (is_root) {
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is_root = false;
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return;
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}
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EXPECT_EQ(input[i], node.value());
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++i;
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}));
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}
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