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SPDX License Identifiers are a more compact / standardized way of representing file license information. See: https://spdx.dev/resources/use/#identifiers This was done with the `ambr` search and replace tool. ambr --no-parent-ignore --key-from-file --rep-from-file key.txt rep.txt *
110 lines
2.9 KiB
C++
110 lines
2.9 KiB
C++
/*
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* Copyright (c) 2020, Nico Weber <thakis@chromium.org>
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*
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* SPDX-License-Identifier: BSD-2-Clause
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*/
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#include <AK/StdLibExtras.h>
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#include <stdio.h>
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#include <stdlib.h>
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#include <string.h>
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#include <unistd.h>
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const char* const g_usage = R"(Usage:
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seq [-h|--help]
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seq LAST
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seq FIRST LAST
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seq FIRST INCREMENT LAST
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)";
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static void print_usage(FILE* stream)
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{
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fputs(g_usage, stream);
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return;
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}
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static double get_double(const char* name, const char* d_string, int* number_of_decimals)
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{
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char* end;
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double d = strtod(d_string, &end);
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if (d == 0 && end == d_string) {
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fprintf(stderr, "%s: invalid argument \"%s\"\n", name, d_string);
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print_usage(stderr);
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exit(1);
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}
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if (char* dot = strchr(d_string, '.'))
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*number_of_decimals = strlen(dot + 1);
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else
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*number_of_decimals = 0;
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return d;
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}
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int main(int argc, const char* argv[])
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{
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if (pledge("stdio", nullptr) < 0) {
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perror("pledge");
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return 1;
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}
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if (unveil(nullptr, nullptr) < 0) {
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perror("unveil");
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return 1;
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}
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for (int i = 1; i < argc; i++) {
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if (strcmp(argv[i], "--help") == 0 || strcmp(argv[i], "-h") == 0) {
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print_usage(stdout);
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exit(0);
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}
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}
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double start = 1, step = 1, end = 1;
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int number_of_start_decimals = 0, number_of_step_decimals = 0, number_of_end_decimals = 0;
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switch (argc) {
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case 2:
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end = get_double(argv[0], argv[1], &number_of_end_decimals);
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break;
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case 3:
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start = get_double(argv[0], argv[1], &number_of_start_decimals);
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end = get_double(argv[0], argv[2], &number_of_end_decimals);
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break;
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case 4:
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start = get_double(argv[0], argv[1], &number_of_start_decimals);
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step = get_double(argv[0], argv[2], &number_of_step_decimals);
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end = get_double(argv[0], argv[3], &number_of_end_decimals);
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break;
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default:
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fprintf(stderr, "%s: unexpected number of arguments\n", argv[0]);
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print_usage(stderr);
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return 1;
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}
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if (step == 0) {
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fprintf(stderr, "%s: increment must not be 0\n", argv[0]);
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return 1;
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}
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if (__builtin_isnan(start) || __builtin_isnan(step) || __builtin_isnan(end)) {
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fprintf(stderr, "%s: start, step, and end must not be NaN\n", argv[0]);
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return 1;
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}
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int number_of_decimals = max(number_of_start_decimals, max(number_of_step_decimals, number_of_end_decimals));
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int n = (end - start) / step;
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double d = start;
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for (int i = 0; i <= n; ++i) {
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char buf[40];
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snprintf(buf, sizeof(buf), "%f", d);
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if (char* dot = strchr(buf, '.')) {
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if (number_of_decimals == 0)
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*dot = '\0';
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else if ((dot - buf) + 1 + number_of_decimals < (int)sizeof(buf))
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dot[1 + number_of_decimals] = '\0';
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}
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printf("%s\n", buf);
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d += step;
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}
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return 0;
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}
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