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Drop results farther than 15 minutes away. #393
It'd be more efficient to terminate the Dijkstra's search directly, but petgraph doesn't have an option for that, so we'll have to implement Dijkstra's manually (shouldn't be hard).
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@ -28,7 +28,9 @@ impl Isochrone {
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);
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// Calculate the cost from the start building to every other building in the map
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for (b, cost) in connectivity::all_costs_from(&app.primary.map, start) {
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for (b, cost) in
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connectivity::all_costs_from(&app.primary.map, start, Duration::minutes(15))
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{
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// What grid cell does the building belong to?
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let pt = app.primary.map.get_b(b).polygon.center();
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let idx = grid.idx(
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@ -47,8 +47,12 @@ pub fn find_scc(map: &Map, constraints: PathConstraints) -> (HashSet<LaneID>, Ha
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}
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/// Starting from one building, calculate the cost to all others. If a destination isn't reachable,
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/// it won't be included in the results.
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pub fn all_costs_from(map: &Map, start: BuildingID) -> HashMap<BuildingID, Duration> {
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/// it won't be included in the results. Ignore results greater than the time_limit away.
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pub fn all_costs_from(
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map: &Map,
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start: BuildingID,
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time_limit: Duration,
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) -> HashMap<BuildingID, Duration> {
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// TODO This is hardcoded to walking; take a PathConstraints.
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let graph = build_graph_for_pedestrians(map);
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let start = WalkingNode::closest(map.get_b(start).sidewalk_pos, map);
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@ -60,7 +64,10 @@ pub fn all_costs_from(map: &Map, start: BuildingID) -> HashMap<BuildingID, Durat
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let mut results = HashMap::new();
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for b in map.all_buildings() {
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if let Some(seconds) = cost_per_node.get(&WalkingNode::closest(b.sidewalk_pos, map)) {
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results.insert(b.id, Duration::seconds(*seconds as f64));
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let duration = Duration::seconds(*seconds as f64);
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if duration <= time_limit {
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results.insert(b.id, duration);
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}
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}
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}
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results
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