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[fix] perl6: $n -> $m

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Martin Kimmerle 2018-11-15 10:46:14 +00:00 committed by GitHub
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@ -246,7 +246,7 @@ sub mutate($n is rw) {
}
my $m = 42;
mutate $m; # $n is now 43 !
mutate $m; # $m is now 43 !
## This works because we are passing the container $m to mutate. If we try
## to just pass a number instead of passing a variable it won't work because