#include <stdint.h>

uint16_t Binary_to_MINUS_int16(uint8_t b1, uint8_t b2) {
    return (uint16_t)(b2 << 8) | b1;
}

uint32_t Binary_to_MINUS_int32(uint8_t b1, uint8_t b2, uint8_t b3, uint8_t b4) {
    return (uint32_t)b1 | (b2 << 8) | (b3 << 16) | (b4 << 24);
}

uint64_t Binary_to_MINUS_int64(uint8_t b1, uint8_t b2, uint8_t b3, uint8_t b4,
                               uint8_t b5, uint8_t b6, uint8_t b7, uint8_t b8) {
    return (uint64_t)b1 | (b2 << 8) | (b3 << 16) | (b4 << 24) |
           ((uint64_t)b5 << 32) | ((uint64_t)b6 << 40) | ((uint64_t)b7 << 48) |
           ((uint64_t)b8 << 56);
}

uint8_t Binary_int16_MINUS_to_MINUS_byte(uint16_t *x) {
    return *x & 0xff;
}

uint8_t Binary_int32_MINUS_to_MINUS_byte(uint32_t *x) {
    return *x & 0xff;
}

uint8_t Binary_int64_MINUS_to_MINUS_byte(uint64_t *x) {
    return *x & 0xff;
}

int Binary_system_MINUS_endianness_MINUS_internal() {
    // The int type is always >= 16 bits, two bytes, according to The C
    // Programming Language, Second Edition. Contrarily, char is always a single
    // byte.
    //
    // Allocating 1 and converting to char will leave us with the first byte
    // used to represent the int. On a little endian machine, we're left with 1
    // on a big endian machine, we're left with 0.
    unsigned int i = 1;
    // Conversion to char lets us access bytes individually.
    // We return the first byte.
    return (int)((char *)&i)[0];
}