Hubert Plociniczak f1e60e7e44 Use simple type name as Jackson type id (#9961) ... Using a fully qualified name for type identifier does not play well when dealing with different classloaders (classes are not recognized as equal/subtypes). Closes #9876. Likely also affecting #9306. # Important Notes There appears to be a number of cases loosely related issues on that subject. Gave up on adding a test cases to simulate the problem but I could no longer reproduce it with LS/runtime on a live project. ``` [org.enso.languageserver.runtime.RuntimeConnector$Endpoint] Failed to deserialize runtime API envelope com.fasterxml.jackson.databind.exc.InvalidTypeIdException: Could not resolve type id 'org.enso.polyglot.data.Tree$Node' as a subtype of `org.enso.polyglot.data.Tree$Node<org.enso.polyglot.runtime.Runtime$Api$SuggestionUpdate>`: Not a subtype at [Source: (byte[])[6718 bytes]; byte offset: #394] (through reference chain: org.enso.polyglot.runtime.Runtime$Api$Response["payload"]->org.enso.polyglot.runtime.Runtime$Api$SuggestionsDatabaseModuleUpdateNotification["updates"]->org.enso.polyglot.data.Tree$Root["children"]->com.fasterxml.jackson.module.scala.deser.GenericFactoryDeserializerResolver$BuilderWrapper[0]) at org.enso.IsolatedClassLoader//com.fasterxml.jackson.databind.exc.InvalidTypeIdException.from(InvalidTypeIdException.java:43) ``` appears to be gone.		2024-05-16 14:26:26 +00:00
..
main	Use simple type name as Jackson type id (#9961)	2024-05-16 14:26:26 +00:00
test/scala/org/enso/polyglot	Syntax error shall contain location of the error (#9864)	2024-05-07 15:15:51 +00:00