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color: cleanup 'debugcolor' logic

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Now that style are carried by the 'ui' object, we no longer need complicated
logic to restore the original style. We just need to copy the 'ui' and work on
the copied version.
This commit is contained in:
Pierre-Yves David 2017-02-25 19:43:14 +01:00
parent 394a984c5e
commit bfa78d1064
1 changed files with 16 additions and 20 deletions
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36
mercurial/debugcommands.py
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@ -357,26 +357,22 @@ def debugcolor(ui, repo, **opts):
return _debugdisplaycolor(ui)
def _debugdisplaycolor(ui):
oldstyle = ui._styles.copy()
try:
ui._styles.clear()
for effect in color._effects.keys():
ui._styles[effect] = effect
if ui._terminfoparams:
for k, v in ui.configitems('color'):
if k.startswith('color.'):
ui._styles[k] = k[6:]
elif k.startswith('terminfo.'):
ui._styles[k] = k[9:]
ui.write(_('available colors:\n'))
# sort label with a '_' after the other to group '_background' entry.
items = sorted(ui._styles.items(),
key=lambda i: ('_' in i[0], i[0], i[1]))
for colorname, label in items:
ui.write(('%s\n') % colorname, label=label)
finally:
ui._styles.clear()
ui._styles.update(oldstyle)
ui = ui.copy()
ui._styles.clear()
for effect in color._effects.keys():
ui._styles[effect] = effect
if ui._terminfoparams:
for k, v in ui.configitems('color'):
if k.startswith('color.'):
ui._styles[k] = k[6:]
elif k.startswith('terminfo.'):
ui._styles[k] = k[9:]
ui.write(_('available colors:\n'))
# sort label with a '_' after the other to group '_background' entry.
items = sorted(ui._styles.items(),
key=lambda i: ('_' in i[0], i[0], i[1]))
for colorname, label in items:
ui.write(('%s\n') % colorname, label=label)
def _debugdisplaystyle(ui):
ui.write(_('available style:\n'))