1
1
mirror of https://github.com/github/semantic.git synced 2024-12-03 00:16:52 +03:00
semantic/prototype/Doubt/SES.swift
2015-11-12 16:13:31 -05:00

84 lines
4.2 KiB
Swift
Raw Blame History

This file contains ambiguous Unicode characters

This file contains Unicode characters that might be confused with other characters. If you think that this is intentional, you can safely ignore this warning. Use the Escape button to reveal them.

/// Computes the SES (shortest edit script), i.e. the shortest sequence of diffs (`Free<Leaf, Annotation, Patch<Term>>`) for two arrays of `Term`s which would suffice to transform `a` into `b`.
///
/// This is computed w.r.t. an `equals` function, which computes the equality of leaf nodes within terms, and a `recur` function, which produces diffs representing matched-up terms.
public func SES<Leaf, Annotation, C: CollectionType>(a: C, _ b: C, cost: Free<Leaf, Annotation, Patch<C.Generator.Element>> -> Int, recur: (C.Generator.Element, C.Generator.Element) -> Free<Leaf, Annotation, Patch<C.Generator.Element>>?) -> [Free<Leaf, Annotation, Patch<C.Generator.Element>>] {
typealias Diff = Free<Leaf, Annotation, Patch<C.Generator.Element>>
if a.isEmpty { return b.map { .Insert($0) } }
if b.isEmpty { return a.map { .Delete($0) } }
// A matrix whose values are streams representing paths through the edit graph, carrying both the diff & the cost of the remainder of the path.
var matrix: Matrix<Stream<(Diff, Int)>, C.Index>!
matrix = Matrix(across: a.startIndex..<a.endIndex.successor(), down: b.startIndex..<b.endIndex.successor()) { i, j in
// Some explanation is warranted:
//
// 1. `matrix` captures itself during construction, because each vertex in the edit graph depends on other vertices. This is safe, because a) `Matrix` populates its fields lazily, and b) vertices only depend on those vertices downwards and rightwards of them.
//
// 2. `matrix` is sized bigger than `a.count` x `b.count`. This is safe, because a) we only get a[i]/b[j] when right/down are non-nil (respectively), and b) right/down are found by looking up elements (i + 1, j) & (i, j + 1) in the matrix, which returns `nil` when out of bounds. So we only access a[i] and b[j] when i and j are in bounds.
let right = matrix[i.successor(), j]
let down = matrix[i, j.successor()]
let diagonal = matrix[i.successor(), j.successor()]
if let diagonal = diagonal, right = right, down = down {
let here = recur(a[i], b[j])
if let diagonalDiff = here {
let hereCost = cost(diagonalDiff)
let diagonalCost = hereCost + (diagonal.value.first?.1 ?? 0)
// If the diff at this vertex is zero-cost, were not going to find a cheaper one either rightwards or downwards. We can therefore short-circuit selecting the best outgoing edge and save ourselves evaluating the entire row rightwards and the entire column downwards from this point.
//
// Thus, in the best case (two equal sequences), we now complete in O(n + m). However, this optimization only applies to equalities at the beginning of the edit graph; once inequalities are encountered, the remainder of the diff is effectively O(nm).
guard hereCost != 0 else { return .Cons((diagonalDiff, diagonalCost), diagonal) }
let rightDiff = Diff.Delete(a[i])
let rightCost = cost(rightDiff) + (right.value.first?.1 ?? 0)
let downDiff = Diff.Insert(b[j])
let downCost = cost(downDiff) + (down.value.first?.1 ?? 0)
if rightCost < downCost && rightCost < diagonalCost {
return .Cons((rightDiff, rightCost), right)
} else if downCost < diagonalCost {
return .Cons((downDiff, downCost), down)
} else {
return .Cons((diagonalDiff, diagonalCost), diagonal)
}
} else {
let rightDiff = Diff.Delete(a[i])
let rightCost = cost(rightDiff) + (right.value.first?.1 ?? 0)
let downDiff = Diff.Insert(b[j])
let downCost = cost(downDiff) + (down.value.first?.1 ?? 0)
if rightCost < downCost {
return .Cons((rightDiff, rightCost), right)
} else {
return .Cons((downDiff, downCost), down)
}
}
}
// right extent of the edit graph; can only move down
if let down = down {
let diff = Diff.Insert(b[j])
let cost = cost(diff) + (down.value.first?.1 ?? 0)
return .Cons((diff, cost), down)
}
// bottom extent of the edit graph; can only move right
if let right = right {
let diff = Diff.Delete(a[i])
let cost = cost(diff) + (right.value.first?.1 ?? 0)
return .Cons((diff, cost), right)
}
// bottom-right corner of the edit graph
return Stream.Nil
}
return Array(matrix[a.startIndex, b.startIndex]!.value.map { diff, _ in diff })
}
import Memo
import Prelude
import Stream