Remove comment from Language.Haskell.Generate

src/Language/Haskell/Generate.hs

@@ -1,39 +1,6 @@
 module Language.Haskell.Generate
-  ( -- $intro
-    module X
+  ( module X
   ) where
 
 import Language.Haskell.Generate.Base as X
 import Language.Haskell.Generate.PreludeDef as X
-
-{- $intro
-    This library allows you to generate type-correct haskell expressions. To use it, you need to import this module:
-
-> import Language.Haskell.Generate
-
-    This will import the methods for generating haskell expressions and also a list of predefined expressions consisting of functions from the haskell Prelude 
-    that you can use to build your own expressions. For example, here is an expression that reads the file 'names':
-
-> readNames :: ExpG (IO String) 
-> readNames = readFile' <>$ expr "names"
-
-    First, look at the type of readNames. @'ExpG'@ is a data type provided by haskell-generate for haskell expressions. We want to generate an expression
-    that returns an IO String, so the type of readNames is @ExpG (IO String)@. 
-    @readFile'@ is an expression for the haskell readFile function. You can use almost any Prelude function in your expression by adding an apostrophe to
-    the end of the function name.
-    We use (<>$) to generate a expression that applies 'readFile' to the expression "names". @'expr'@ automagically generates a literal expression.
-
-    Now that we have an expression to read the @names@ file, we can generate a module with it:
-
-> myModule :: ModuleG
-> myModule = do
->   readNamesDecl <- addDecl (Ident "readNames") readNames
->   return $ Just [exportFun readNamesDecl]
-
-    
-
-> main :: IO ()
-> main = do
->   putStrLn $ generateModule myModule "FooBar"
-
--}