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translateX/Y: fix negative translations
This change makes it so that translating an image negatively will return an empty image if the negative translation completely hides the input image. Previously we'd just return an image with a negative height, which not only violates the requirement that all images have height no less than zero, but it caused downstream bugs in mutable vector accesses due to negative vector indices.
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@ -242,6 +242,7 @@ translate x y i = translateX x (translateY y i)
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-- | Translates an image by padding or cropping its left side.
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-- | Translates an image by padding or cropping its left side.
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translateX :: Int -> Image -> Image
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translateX :: Int -> Image -> Image
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translateX x i
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translateX x i
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| x < 0 && (abs x > imageWidth i) = emptyImage
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| x < 0 = let s = abs x in CropLeft i s (imageWidth i - s) (imageHeight i)
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| x < 0 = let s = abs x in CropLeft i s (imageWidth i - s) (imageHeight i)
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| x == 0 = i
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| x == 0 = i
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| otherwise = let h = imageHeight i in HorizJoin (BGFill x h) i (imageWidth i + x) h
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| otherwise = let h = imageHeight i in HorizJoin (BGFill x h) i (imageWidth i + x) h
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@ -249,6 +250,7 @@ translateX x i
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-- | Translates an image by padding or cropping its top.
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-- | Translates an image by padding or cropping its top.
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translateY :: Int -> Image -> Image
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translateY :: Int -> Image -> Image
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translateY y i
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translateY y i
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| y < 0 && (abs y > imageHeight i) = emptyImage
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| y < 0 = let s = abs y in CropTop i s (imageWidth i) (imageHeight i - s)
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| y < 0 = let s = abs y in CropTop i s (imageWidth i) (imageHeight i - s)
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| y == 0 = i
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| y == 0 = i
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| otherwise = let w = imageWidth i in VertJoin (BGFill w y) i w (imageHeight i + y)
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| otherwise = let w = imageWidth i in VertJoin (BGFill w y) i w (imageHeight i + y)
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