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214 lines
6.7 KiB
Elm
214 lines
6.7 KiB
Elm
module NoSimpleLetBody exposing (rule)
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{-|
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@docs rule
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-}
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import Elm.Syntax.Expression as Expression exposing (Expression)
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import Elm.Syntax.Node as Node exposing (Node)
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import Elm.Syntax.Range exposing (Location, Range)
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import Review.Fix as Fix exposing (Fix)
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import Review.Rule as Rule exposing (Rule)
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{-| Reports when a let expression's body is a simple reference to a value declared in the let expression.
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🔧 Running with `--fix` will automatically remove most of the reported errors.
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config =
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[ NoSimpleLetBody.rule
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]
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The reasoning is that it is not necessary to assign a name to the result of a let expression,
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since they are redundant with the value or function containing the expression.
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If it feels necessary to give a name anyway because it helps clarify the context, then it might be a sign that the computation of that value should be extracted to a function.
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Let expressions will be reported regardless of whether they're at the root of a function or deeply nested.
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## Fail
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a =
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let
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b =
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1
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c =
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b + 1
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in
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c
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## Success
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Anything that is not simply a reference to a value declared in the let expression is okay.
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a =
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let
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b =
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1
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in
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b + 1
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The rule will not report when the referenced value was destructured in the let expression.
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first tuple =
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let
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( value, _ ) =
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tuple
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in
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value
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## When (not) to enable this rule
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This rule resolves a minor style issue, and may not be worth enforcing depending on how strongly you feel about this issue.
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## Try it out
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You can try this rule out by running the following command:
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```bash
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elm-review --template jfmengels/elm-review-code-style/example --rules NoSimpleLetBody
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```
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-}
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rule : Rule
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rule =
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Rule.newModuleRuleSchema "NoSimpleLetBody" ()
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|> Rule.withSimpleExpressionVisitor expressionVisitor
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|> Rule.fromModuleRuleSchema
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expressionVisitor : Node Expression -> List (Rule.Error {})
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expressionVisitor node =
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case Node.value node of
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Expression.LetExpression letBlock ->
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visitLetExpression (Node.range node) letBlock
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_ ->
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[]
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visitLetExpression : Range -> Expression.LetBlock -> List (Rule.Error {})
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visitLetExpression nodeRange { declarations, expression } =
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case Node.value expression of
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Expression.FunctionOrValue [] name ->
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let
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declarationData :
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{ previousEnd : Maybe Location
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, lastEnd : Maybe Location
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, last : Maybe { name : String, expressionRange : Range }
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, foundDeclaredWithName : Bool
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}
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declarationData =
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getDeclarationsData name declarations
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in
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if declarationData.foundDeclaredWithName then
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[ Rule.errorWithFix
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{ message = "The referenced value should be inlined."
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, details =
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[ "The name of the value is redundant with the surrounding expression."
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, "If you believe that the expression needs a name because it is too complex, consider splitting the expression up more or extracting it to a new function."
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]
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}
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(Node.range expression)
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(fix nodeRange name declarationData)
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]
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else
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[]
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_ ->
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[]
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getDeclarationsData :
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String
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-> List (Node Expression.LetDeclaration)
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->
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{ previousEnd : Maybe Location
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, lastEnd : Maybe Location
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, last : Maybe { name : String, expressionRange : Range }
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, foundDeclaredWithName : Bool
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}
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getDeclarationsData name declarations =
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List.foldl
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(\declaration { lastEnd, foundDeclaredWithName } ->
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case Node.value declaration of
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Expression.LetFunction function ->
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let
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functionDeclaration : Expression.FunctionImplementation
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functionDeclaration =
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Node.value function.declaration
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in
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{ previousEnd = lastEnd
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, lastEnd = Just (Node.range functionDeclaration.expression).end
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, last =
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if List.isEmpty functionDeclaration.arguments then
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Just
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{ name = Node.value functionDeclaration.name
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, expressionRange = Node.range functionDeclaration.expression
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}
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else
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Nothing
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, foundDeclaredWithName = foundDeclaredWithName || Node.value functionDeclaration.name == name
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}
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Expression.LetDestructuring _ _ ->
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{ previousEnd = lastEnd
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, lastEnd = Just (Node.range declaration).end
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, last = Nothing
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, foundDeclaredWithName = foundDeclaredWithName
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}
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)
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{ previousEnd = Nothing
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, lastEnd = Nothing
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, last = Nothing
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, foundDeclaredWithName = False
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}
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declarations
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fix :
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Range
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-> String
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->
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{ r
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| previousEnd : Maybe Location
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, last : Maybe { name : String, expressionRange : Range }
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}
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-> List Fix
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fix nodeRange name declarationData =
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case declarationData.last of
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Just last ->
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if last.name == name then
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case declarationData.previousEnd of
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Nothing ->
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-- It's the only element in the destructuring, we should remove move of the let expression
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[ Fix.removeRange { start = nodeRange.start, end = last.expressionRange.start }
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, Fix.removeRange { start = last.expressionRange.end, end = nodeRange.end }
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]
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Just previousEnd ->
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-- There are other elements in the let body that we need to keep
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let
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indentation : String
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indentation =
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String.repeat (nodeRange.start.column - 1) " "
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in
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[ Fix.replaceRangeBy { start = previousEnd, end = last.expressionRange.start } ("\n" ++ indentation ++ "in\n" ++ indentation)
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, Fix.removeRange { start = last.expressionRange.end, end = nodeRange.end }
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]
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else
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[]
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Nothing ->
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[]
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