3foo0 f g x y = proc _ -> (|f (g -< (x, y))|)
5foo1 f g h x = proc (y, z) ->
6 (|test (h f . (h g) -< (y x) . y z) ((h g) . h f -< y z . (y x))|)
8foo2 f g h x = proc (y, z) ->
22bar0 f g x y = proc _ -> f -< x &&& g -< y
24bar1 f g h x = proc (y, z) ->
25 h f . (h g) -< (y x) . y z ||| (h g) . h f -< y z . (y x)
27bar2 f g h x = proc (y, z) ->
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