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Don't recompute pair boolean when building token

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Pass in hasPairedCharacter to the Token constructor when it is
being broken out from the parent token instead of recomputing it.
This commit is contained in:
Kevin Sawicki 2014-10-28 18:02:57 -07:00
parent 54260230c6
commit 9abc4580f4
1 changed files with 3 additions and 2 deletions
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5
src/token.coffee
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@ -21,10 +21,10 @@ class Token
firstTrailingWhitespaceIndex: null
hasInvisibleCharacters: false
constructor: ({@value, @scopes, @isAtomic, @bufferDelta, @isHardTab}) ->
constructor: ({@value, @scopes, @isAtomic, @bufferDelta, @isHardTab, @hasPairedCharacter}) ->
@screenDelta = @value.length
@bufferDelta ?= @screenDelta
@hasPairedCharacter = textUtils.hasPairedCharacter(@value)
@hasPairedCharacter ?= textUtils.hasPairedCharacter(@value)
isEqual: (other) ->
# TODO: scopes is deprecated. This is here for the sake of lang package tests
@ -125,6 +125,7 @@ class Token
value: value[index..index + 1]
scopes: @scopes
isAtomic: true
hasPairedCharacter: true
)
buildHardTabToken: (tabLength, column) ->