5test1 :: forall a. (a -> a) -> a -> a
11test2 :: forall a. (a -> a) -> a -> a
14 h :: forall b. (b -> b) -> b -> b
21test3 = ((\b -> b :: b) :: forall b. b -> b) 0.0
23test4 :: forall a. (a -> a) -> a -> a
26 h :: forall b. (b -> b) -> b -> b
36main = Control.Monad.Eff.Console.log "Done"
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