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More changes to order and aesthetics
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README.md
vendored
188
README.md
vendored
@ -1303,7 +1303,7 @@ NameError: name 'e' is not defined
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* Source: https://docs.python.org/3/reference/compound_stmts.html#except
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When an exception has been assigned using `as` target, it is cleared at the end of the except clause. This is as if
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When an exception has been assigned using `as` target, it is cleared at the end of the `except` clause. This is as if
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```py
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except E as N:
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@ -1378,8 +1378,75 @@ I've lost faith in truth!
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---
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### ▶ Yielding from... return!
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1\.
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```py
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def some_func(x):
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if x == 3:
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return ["wtf"]
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else:
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yield from range(x)
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```
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**Output:**
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```py
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>>> list(some_func(3))
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[]
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```
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Where did the `"wtf"` go? Is it due to some special effect of `yield from`? Let's validate that,
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2\.
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```py
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def some_func(x):
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if x == 3:
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return ["wtf"]
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else:
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for i in range(x):
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yield i
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```
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**Output (> 3.3):**
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```py
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>>> list(some_func(3))
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[]
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```
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Same result, that didn't work either.
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#### 💡 Explanation:
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+ From Python 3.3 onwards, it became possible to use `return` statement with values inside generators (See [PEP380](https://www.python.org/dev/peps/pep-0380/)). The [official docs](https://www.python.org/dev/peps/pep-0380/#enhancements-to-stopiteration) say that,
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> "... `return expr` in a generator causes `StopIteration(expr)` to be raised upon exit from the generator."
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+ In case of `some_func(3)`, `StopIteration` is raised at the beginning because of `return` statement. The `StopIteration` exception is automatically catched inside the `list(...)` wrapper and the `for` loop. Therefore, the above two snippets result in an empty list.
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+ To get `["wtf"]` from the generator `some_func` we need to catch the `StopIteration` exception,
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```py
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try:
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next(some_func(3))
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except StopIteration as e:
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some_string = e.value
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```
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```py
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>>> some_string
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["wtf"]
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```
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---
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### ▶ Lossy zip of iterators
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<!-- Example ID: c28ed154-e59f-4070-8eb6-8967a4acac6d --->
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```py
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>>> numbers = list(range(7))
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>>> numbers
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@ -1407,8 +1474,7 @@ Where did element `3` go from the `numbers` list?
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result = []
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for it in iterators:
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elem = next(it, sentinel)
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if elem is sentinel:
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return
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if elem is sentinel: return
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result.append(elem)
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yield tuple(result)
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```
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@ -1605,7 +1671,9 @@ The built-in `ord()` function returns a character's Unicode [code point](https:/
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---
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### ▶ Teleportation
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<!-- Example ID: edafe923-0c20-4315-b6e1-0c31abfc38f5 --->
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```py
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import numpy as np
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@ -1858,8 +1926,8 @@ print(x, ': x in global')
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>>> x = 1
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>>> print([x for x in range(5)])
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[0, 1, 2, 3, 4]
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>>> print(x, ': x in global')
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(4, ': x in global')
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>>> print(x)
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4
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```
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**Output (Python 3.x):**
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@ -1867,15 +1935,15 @@ print(x, ': x in global')
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>>> x = 1
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>>> print([x for x in range(5)])
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[0, 1, 2, 3, 4]
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>>> print(x, ': x in global')
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1 : x in global
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>>> print(x)
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1
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```
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#### 💡 Explanation:
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- In Python, for-loops use the scope they exist in and leave their defined loop-variable behind. This also applies if we explicitly defined the for-loop variable in the global namespace before. In this case, it will rebind the existing variable.
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- The differences in the output of Python 2.x and Python 3.x interpreters for list comprehension example can be explained by following change documented in [What’s New In Python 3.0](https://docs.python.org/3/whatsnew/3.0.html) documentation:
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- The differences in the output of Python 2.x and Python 3.x interpreters for list comprehension example can be explained by following change documented in [What’s New In Python 3.0](https://docs.python.org/3/whatsnew/3.0.html) change log:
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> "List comprehensions no longer support the syntactic form `[... for var in item1, item2, ...]`. Use `[... for var in (item1, item2, ...)]` instead. Also, note that list comprehensions have different semantics: they are closer to syntactic sugar for a generator expression inside a `list()` constructor, and in particular the loop control variables are no longer leaked into the surrounding scope."
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@ -1883,6 +1951,7 @@ print(x, ': x in global')
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### ▶ Beware of default mutable arguments!
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<!-- Example ID: 7d42dade-e20d-4a7b-9ed7-16fb58505fe9 --->
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```py
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def some_func(default_arg=[]):
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default_arg.append("some_string")
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@ -2182,39 +2251,6 @@ class SomeClass:
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---
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### ▶ From full to None in one instruction
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<!-- Example ID: 9a0d5335-efe5-4eae-af44-584d15233066 --->
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```py
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some_list = [1, 2, 3]
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some_dict = {
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"key_1": 1,
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"key_2": 2,
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"key_3": 3
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}
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some_list = some_list.append(4)
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some_dict = some_dict.update({"key_4": 4})
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```
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**Output:**
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```py
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>>> print(some_list)
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None
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>>> print(some_dict)
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None
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```
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#### 💡 Explanation
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---
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### ▶ Needles in a Haystack
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<!-- Example ID: 52a199b1-989a-4b28-8910-dff562cebba9 --->
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@ -2235,6 +2271,7 @@ x, y = (0, 1) if True else None, None
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```
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2\.
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```py
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t = ('one', 'two')
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for i in t:
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@ -2249,6 +2286,7 @@ print(t)
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```
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**Output:**
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```py
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one
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two
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@ -2288,7 +2326,9 @@ ten_words_list = [
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a = "python"
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b = "javascript"
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```
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**Output:**
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```py
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# An assert statement with an assertion failure message.
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>>> assert(a == b, "Both languages are different")
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@ -2329,12 +2369,14 @@ None
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* `()` is a special token and denotes empty `tuple`.
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* In 3, as you might have already figured out, there's a missing comma after 5th element (`"that"`) in the list. So by implicit string literal concatenation,
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```py
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>>> ten_words_list
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['some', 'very', 'big', 'list', 'thatconsists', 'of', 'exactly', 'ten', 'words']
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```
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* No `AssertionError` was raised in 4th snippet because instead of asserting the individual expression `a == b`, we're asserting entire tuple. The following snippet will clear things up,
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```py
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>>> a = "python"
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>>> b = "javascript"
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@ -2358,70 +2400,6 @@ None
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---
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### ▶ Yielding from... return!
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1\.
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```py
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def some_func(x):
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if x == 3:
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return ["wtf"]
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else:
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yield from range(x)
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```
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**Output:**
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```py
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>>> list(some_func(3))
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[]
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```
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Where did the `"wtf"` go? Is it due to some special effect of `yield from`? Let's validate that,
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2\.
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```py
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def some_func(x):
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if x == 3:
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return ["wtf"]
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else:
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for i in range(x):
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yield i
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```
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**Output (> 3.3):**
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```py
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>>> list(some_func(3))
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[]
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```
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Same result, that didn't work either.
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#### 💡 Explanation:
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+ From Python 3.3 onwards, it became possible to use `return` statement with values inside generators (See [PEP380](https://www.python.org/dev/peps/pep-0380/)). The [official docs](https://www.python.org/dev/peps/pep-0380/#enhancements-to-stopiteration) say that,
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> "... `return expr` in a generator causes `StopIteration(expr)` to be raised upon exit from the generator."
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+ In case of `some_func(3)`, `StopIteration` is raised at the beginning because of `return` statement. The `StopIteration` exception is automatically catched inside the `list(...)` wrapper and the `for` loop. Therefore, the above two snippets result in an empty list.
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+ To get `["wtf"]` from the generator `some_func` we need to catch the `StopIteration` exception,
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```py
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try:
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next(some_func(3))
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except StopIteration as e:
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some_string = e.value
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```
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```py
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>>> some_string
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["wtf"]
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```
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---
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### ▶ Wild imports
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<!-- Example ID: 83deb561-bd55-4461-bb5e-77dd7f411e1c --->
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```py
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