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Correctify explanation of Stubborn del
operation
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README.md
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README.md
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@ -1954,7 +1954,7 @@ class SomeClass:
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Deleted!
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```
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Phew, deleted at last. You might have guessed what saved from `__del__` being called in our first attempt to delete `x`. Let's add more twists to the example.
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Phew, deleted at last. You might have guessed what saved `__del__` from being called in our first attempt to delete `x`. Let's add more twists to the example.
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2\.
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```py
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@ -1973,9 +1973,9 @@ Okay, now it's deleted :confused:
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#### 💡 Explanation:
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+ `del x` doesn’t directly call `x.__del__()`.
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+ Whenever `del x` is encountered, Python decrements the reference count for `x` by one, and `x.__del__()` when x’s reference count reaches zero.
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+ In the second output snippet, `y.__del__()` was not called because the previous statement (`>>> y`) in the interactive interpreter created another reference to the same object, thus preventing the reference count from reaching zero when `del y` was encountered.
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+ Calling `globals` caused the existing reference to be destroyed, and hence we can see "Deleted!" being printed (finally!).
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+ When `del x` is encountered, Python deletes the name `x` from current scope and decrements by 1 the reference count of the object `x` referenced. `__del__()` is called only when the object's reference count reaches zero.
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+ In the second output snippet, `__del__()` was not called because the previous statement (`>>> y`) in the interactive interpreter created another reference to the same object (specifically, the `_` magic variable which references the result value of the last non `None` expression on the REPL), thus preventing the reference count from reaching zero when `del y` was encountered.
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+ Calling `globals` (or really, executing anything that will have a non `None` result) caused `_` to reference the new result, dropping the existing reference. Now the reference count reached 0 and we can see "Deleted!" being printed (finally!).
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---
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