module Amount where import Utils import Types import Currency {- a simple amount is a currency, quantity pair: $1 £-50 EUR 3.44 GOOG 500 1.5h 90m 0 a mixed amount is one or more simple amounts: $50, EUR 3, AAPL 500 16h, $13.55, oranges 6 arithmetic: $1 - $5 = $-4 $1 + EUR 0.76 = $2 EUR0.76 + $1 = EUR 1.52 EUR0.76 - $1 = 0 ($5, 2h) + $1 = ($6, 2h) ($50, EUR 3, AAPL 500) + ($13.55, oranges 6) = $67.51, AAPL 500, oranges 6 ($50, EUR 3) * $-1 = $-53.96 ($50, AAPL 500) * $-1 = error -} tests = runTestTT $ test [ show (dollars 1) ~?= "$1.00" ,show (hours 1) ~?= "1h" -- currently h1.00 ,parseAmount "$1" ~?= dollars 1 -- currently 0 ] nullamt = dollars 0 parseAmount :: String -> Amount parseAmount s = nullamt instance Show Amount where show = showAmountRounded showAmountRounded :: Amount -> String showAmountRounded (Amount c q p) = (symbol c) ++ ({-punctuatethousands $ -}printf ("%."++show p++"f") q) showAmountRoundedOrZero :: Amount -> String showAmountRoundedOrZero a@(Amount c _ _) = let s = showAmountRounded a noncurrency = drop (length $ symbol c) nonnulls = filter (flip notElem "-+,.0") iszero = (nonnulls $ noncurrency s) == "" in if iszero then "0" else s punctuatethousands :: String -> String punctuatethousands s = sign ++ (punctuate int) ++ frac where (sign,num) = break isDigit s (int,frac) = break (=='.') num punctuate = reverse . concat . intersperse "," . triples . reverse triples "" = [] triples s = [take 3 s] ++ (triples $ drop 3 s) instance Num Amount where abs (Amount c q p) = Amount c (abs q) p signum (Amount c q p) = Amount c (signum q) p fromInteger i = Amount (getcurrency "$") (fromInteger i) amtintprecision (+) = amountop (+) (-) = amountop (-) (*) = amountop (*) -- problem: when an integer is converted to an amount it must pick a -- precision, which we specify here (should be infinite ?). This can -- affect amount arithmetic, in particular the sum of a list of amounts. -- So, we may need to adjust the precision after summing amounts. amtintprecision = 2 -- apply op to two amounts, adopting a's currency and lowest precision amountop :: (Double -> Double -> Double) -> Amount -> Amount -> Amount amountop op (Amount ac aq ap) b@(Amount _ _ bp) = Amount ac (aq `op` (quantity $ toCurrency ac b)) (min ap bp) toCurrency :: Currency -> Amount -> Amount toCurrency newc (Amount oldc q p) = Amount newc (q * (conversionRate oldc newc)) p