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185 lines
6.0 KiB
Haskell
185 lines
6.0 KiB
Haskell
{-|
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A ledger-compatible @balance@ command. Here's how it should work:
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A sample account tree (as in the sample.ledger file):
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@
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assets
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cash
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checking
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saving
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expenses
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food
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supplies
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income
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gifts
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salary
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liabilities
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debts
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@
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The balance command shows top-level accounts by default:
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@
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\> ledger balance
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$-1 assets
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$2 expenses
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$-2 income
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$1 liabilities
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@
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With -s (--showsubs), also show the subaccounts:
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@
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$-1 assets
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$-2 cash
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$1 saving
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$2 expenses
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$1 food
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$1 supplies
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$-2 income
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$-1 gifts
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$-1 salary
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$1 liabilities:debts
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@
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- @checking@ is not shown because it has a zero balance and no interesting
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subaccounts.
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- @liabilities@ is displayed only as a prefix because it has the same balance
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as its single subaccount.
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With an account pattern, show only the accounts with matching names:
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@
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\> ledger balance o
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$1 expenses:food
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$-2 income
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--------------------
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$-1
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@
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- The o matched @food@ and @income@, so they are shown.
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- Parents of matched accounts are also shown for context (@expenses@).
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- This time the grand total is also shown, because it is not zero.
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Again, -s adds the subaccounts:
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@
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\> ledger -s balance o
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$1 expenses:food
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$-2 income
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$-1 gifts
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$-1 salary
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--------------------
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$-1
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@
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- @food@ has no subaccounts. @income@ has two, so they are shown.
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- We do not add the subaccounts of parents included for context (@expenses@).
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Some notes for the implementation:
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- a simple balance report shows top-level accounts
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- with an account pattern, it shows accounts whose leafname matches, plus their parents
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- with the showsubs option, it also shows all subaccounts of the above
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- zero-balance leaf accounts are removed
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- the resulting account tree is displayed with each account's aggregated
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balance, with boring parents prefixed to the next line
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- a boring parent has the same balance as its child and is not explicitly
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matched by the display options.
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- the sum of the balances shown is displayed at the end, if it is non-zero
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-}
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module BalanceCommand
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where
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import Ledger.Utils
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import Ledger.Types
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import Ledger.Amount
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import Ledger.AccountName
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import Ledger.Ledger
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import Options
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import Utils
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-- | Print a balance report.
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balance :: [Opt] -> [String] -> Ledger -> IO ()
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balance opts args l = putStr $ showBalanceReport opts args l
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-- | Generate balance report output for a ledger, based on options.
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showBalanceReport :: [Opt] -> [String] -> Ledger -> String
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showBalanceReport opts args l = acctsstr ++ totalstr
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where
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acctsstr = concatMap (showAccountTreeWithBalances acctnamestoshow) $ subs treetoshow
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totalstr = if isZeroAmount total
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then ""
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else printf "--------------------\n%20s\n" $ showAmount total
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showingsubs = ShowSubs `elem` opts
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pats@(apats,dpats) = parseAccountDescriptionArgs args
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maxdepth = if null args && not showingsubs then 1 else 9999
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acctstoshow = balancereportaccts showingsubs apats l
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acctnamestoshow = map aname acctstoshow
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treetoshow = pruneZeroBalanceLeaves $ pruneUnmatchedAccounts $ treeprune maxdepth $ ledgerAccountTree 9999 l
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total = sumAmounts $ map abalance $ nonredundantaccts
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nonredundantaccts = filter (not . hasparentshowing) acctstoshow
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hasparentshowing a = (parentAccountName $ aname a) `elem` acctnamestoshow
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-- select accounts for which we should show balances, based on the options
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balancereportaccts :: Bool -> [String] -> Ledger -> [Account]
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balancereportaccts False [] l = topAccounts l
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balancereportaccts False pats l = accountsMatching pats l
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balancereportaccts True pats l = addsubaccts l $ balancereportaccts False pats l
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-- add (in tree order) any missing subacccounts to a list of accounts
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addsubaccts :: Ledger -> [Account] -> [Account]
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addsubaccts l as = concatMap addsubs as where addsubs = maybe [] flatten . ledgerAccountTreeAt l
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-- remove any accounts from the tree which are not one of the acctstoshow,
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-- or one of their parents, or one of their subaccounts when doing --showsubs
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pruneUnmatchedAccounts :: Tree Account -> Tree Account
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pruneUnmatchedAccounts = treefilter matched
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where
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matched (Account name _ _)
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| name `elem` acctnamestoshow = True
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| any (name `isAccountNamePrefixOf`) acctnamestoshow = True
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| showingsubs && any (`isAccountNamePrefixOf` name) acctnamestoshow = True
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| otherwise = False
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-- remove zero-balance leaf accounts (recursively)
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pruneZeroBalanceLeaves :: Tree Account -> Tree Account
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pruneZeroBalanceLeaves = treefilter (not . isZeroAmount . abalance)
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-- | Show a tree of accounts with balances, for the balance report,
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-- eliding boring parent accounts. Requires a list of the account names we
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-- are interested in to help with that.
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showAccountTreeWithBalances :: [AccountName] -> Tree Account -> String
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showAccountTreeWithBalances matchedacctnames =
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showAccountTreeWithBalances' matchedacctnames 0 ""
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where
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showAccountTreeWithBalances' :: [AccountName] -> Int -> String -> Tree Account -> String
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showAccountTreeWithBalances' matchedacctnames indentlevel prefix (Node (Account fullname _ bal) subs) =
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if isboringparent then showsubswithprefix else showacct ++ showsubswithindent
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where
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showsubswithprefix = showsubs indentlevel (fullname++":")
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showsubswithindent = showsubs (indentlevel+1) ""
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showsubs i p = concatMap (showAccountTreeWithBalances' matchedacctnames i p) subs
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showacct = showbal ++ " " ++ indent ++ prefix ++ leafname ++ "\n"
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showbal = printf "%20s" $ show bal
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indent = replicate (indentlevel * 2) ' '
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leafname = accountLeafName fullname
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numsubs = length subs
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subbal = abalance $ root $ head subs
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matched = fullname `elem` matchedacctnames
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isboringparent = numsubs >= 1 && (bal == subbal || not matched)
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