hledger/Ledger/Utils.hs

99 lines
2.5 KiB
Haskell

{-|
Standard always-available imports and utilities.
-}
module Ledger.Utils (
module Ledger.Utils,
module Char,
module Data.List,
module Data.Tree,
module Data.Ord,
module Data.Maybe,
module Text.Printf,
module Text.Regex,
module Debug.Trace,
module Test.QuickCheck,
module Test.HUnit,
defaultTimeLocale, UTCTime, diffUTCTime, parseTime, formatTime,
)
where
import Char
import Data.List
import Data.Tree
import qualified Data.Map
import Data.Ord
import Data.Maybe
import Text.Printf
import Text.Regex
import Debug.Trace
import Test.QuickCheck hiding (test, Testable)
import Test.HUnit
import System.Locale (defaultTimeLocale)
import Data.Time.Clock (UTCTime, diffUTCTime)
import Data.Time.Format (ParseTime, parseTime, formatTime)
-- time
-- | Parse a date-time string to a time type, or raise an error.
parsedatetime :: ParseTime t => String -> t
parsedatetime s =
parsetimewith "%Y/%m/%d %H:%M:%S" s $
error $ printf "could not parse timestamp \"%s\"" s
-- | Parse a date string to a time type, or raise an error.
parsedate :: ParseTime t => String -> t
parsedate s =
parsetimewith "%Y/%m/%d" s $
error $ printf "could not parse date \"%s\"" s
-- | Parse a time string to a time type using the provided pattern, or
-- return the default.
parsetimewith :: ParseTime t => String -> String -> t -> t
parsetimewith pat s def = fromMaybe def $ parseTime defaultTimeLocale pat s
-- lists
splitAtElement :: Eq a => a -> [a] -> [[a]]
splitAtElement e l =
case dropWhile (e==) l of
[] -> []
l' -> first : splitAtElement e rest
where
(first,rest) = break (e==) l'
-- trees
-- aliases
root = rootLabel
branches = subForest
-- remove all nodes past a certain depth
treeprune :: Int -> Tree a -> Tree a
treeprune 0 t = Node (root t) []
treeprune d t = Node (root t) (map (treeprune $ d-1) $ branches t)
-- apply f to all tree nodes
treemap :: (a -> b) -> Tree a -> Tree b
treemap f t = Node (f $ root t) (map (treemap f) $ branches t)
-- remove all subtrees whose nodes do not fulfill predicate
treefilter :: (a -> Bool) -> Tree a -> Tree a
treefilter f t = Node
(root t)
(map (treefilter f) $ filter (treeany f) $ branches t)
-- is predicate true in any node of tree ?
treeany :: (a -> Bool) -> Tree a -> Bool
treeany f t = (f $ root t) || (any (treeany f) $ branches t)
-- treedrop -- remove the leaves which do fulfill predicate.
-- treedropall -- do this repeatedly.
-- debugging
strace a = trace (show a) a -- trace a showable expression