hledger/AccountName.hs
2007-07-09 18:54:41 +00:00

82 lines
2.9 KiB
Haskell

module AccountName
where
import Utils
import Types
sepchar = ':'
accountNameComponents :: AccountName -> [String]
accountNameComponents = splitAtElement sepchar
accountNameFromComponents :: [String] -> AccountName
accountNameFromComponents = concat . intersperse [sepchar]
accountLeafName :: AccountName -> String
accountLeafName = last . accountNameComponents
accountNameLevel :: AccountName -> Int
accountNameLevel "" = 0
accountNameLevel a = (length $ filter (==sepchar) a) + 1
-- ["a:b:c","d:e"] -> ["a","a:b","a:b:c","d","d:e"]
expandAccountNames :: [AccountName] -> [AccountName]
expandAccountNames as = nub $ concat $ map expand as
where expand as = map accountNameFromComponents (tail $ inits $ accountNameComponents as)
-- ["a:b:c","d:e"] -> ["a","d"]
topAccountNames :: [AccountName] -> [AccountName]
topAccountNames as = [a | a <- expandAccountNames as, accountNameLevel a == 1]
parentAccountName :: AccountName -> AccountName
parentAccountName a = accountNameFromComponents $ init $ accountNameComponents a
parentAccountNames :: AccountName -> [AccountName]
parentAccountNames a = parentAccountNames' $ parentAccountName a
where
parentAccountNames' "" = []
parentAccountNames' a = [a] ++ (parentAccountNames' $ parentAccountName a)
isAccountNamePrefixOf :: AccountName -> AccountName -> Bool
p `isAccountNamePrefixOf` s = ((p ++ [sepchar]) `isPrefixOf` s)
isSubAccountNameOf :: AccountName -> AccountName -> Bool
s `isSubAccountNameOf` p =
(p `isAccountNamePrefixOf` s) && (accountNameLevel s == (accountNameLevel p + 1))
subAccountNamesFrom :: [AccountName] -> AccountName -> [AccountName]
subAccountNamesFrom accts a = filter (`isSubAccountNameOf` a) accts
matchAccountName :: Regex -> AccountName -> Bool
matchAccountName r a =
case matchRegex r a of
Nothing -> False
otherwise -> True
indentAccountName :: Int -> AccountName -> String
indentAccountName indentcorrection a =
replicate (indentlevel * 2) ' ' ++ (accountLeafName a)
where indentlevel = ((accountNameLevel a) - 1) + indentcorrection
-- We could almost get by with just the above, but we need smarter
-- structures to eg display the account tree with boring accounts elided.
-- first, here is a tree of AccountNames; Account and Account tree are
-- defined later.
accountNameTreeFrom_props =
[
accountNameTreeFrom ["a"] == Node "top" [Node "a" []],
accountNameTreeFrom ["a","b"] == Node "top" [Node "a" [], Node "b" []],
accountNameTreeFrom ["a","a:b"] == Node "top" [Node "a" [Node "a:b" []]],
accountNameTreeFrom ["a:b"] == Node "top" [Node "a" [Node "a:b" []]]
]
accountNameTreeFrom :: [AccountName] -> Tree AccountName
accountNameTreeFrom accts =
Node "top" (accountsFrom (topAccountNames accts))
where
accountsFrom :: [AccountName] -> [Tree AccountName]
accountsFrom [] = []
accountsFrom as = [Node a (accountsFrom $ subs a) | a <- as]
subs = (subAccountNamesFrom accts)