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52 lines
1.6 KiB
TypeScript
52 lines
1.6 KiB
TypeScript
// Loaded from https://deno.land/x/ramda@v0.27.2/source/groupWith.js
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import _curry2 from './internal/_curry2.js';
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/**
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* Takes a list and returns a list of lists where each sublist's elements are
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* all satisfied pairwise comparison according to the provided function.
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* Only adjacent elements are passed to the comparison function.
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*
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* @func
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* @memberOf R
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* @since v0.21.0
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* @category List
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* @sig ((a, a) → Boolean) → [a] → [[a]]
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* @param {Function} fn Function for determining whether two given (adjacent)
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* elements should be in the same group
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* @param {Array} list The array to group. Also accepts a string, which will be
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* treated as a list of characters.
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* @return {List} A list that contains sublists of elements,
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* whose concatenations are equal to the original list.
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* @example
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*
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* R.groupWith(R.equals, [0, 1, 1, 2, 3, 5, 8, 13, 21])
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* //=> [[0], [1, 1], [2], [3], [5], [8], [13], [21]]
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*
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* R.groupWith((a, b) => a + 1 === b, [0, 1, 1, 2, 3, 5, 8, 13, 21])
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* //=> [[0, 1], [1, 2, 3], [5], [8], [13], [21]]
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*
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* R.groupWith((a, b) => a % 2 === b % 2, [0, 1, 1, 2, 3, 5, 8, 13, 21])
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* //=> [[0], [1, 1], [2], [3, 5], [8], [13, 21]]
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*
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* const isVowel = R.test(/^[aeiou]$/i);
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* R.groupWith(R.eqBy(isVowel), 'aestiou')
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* //=> ['ae', 'st', 'iou']
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*/
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var groupWith = _curry2(function(fn, list) {
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var res = [];
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var idx = 0;
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var len = list.length;
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while (idx < len) {
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var nextidx = idx + 1;
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while (nextidx < len && fn(list[nextidx - 1], list[nextidx])) {
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nextidx += 1;
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}
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res.push(list.slice(idx, nextidx));
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idx = nextidx;
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}
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return res;
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});
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export default groupWith;
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