@@ -15,7 +15,7 @@ Now we're going to cover the boiler plate that we skimmed over earlier.
15 =< (sum [1.000 2.000])
15 =< (sum [1.000 2.000])
17The first rune, `:-` (colhep, aka
17The first rune, `:-` (colhep, aka
18−[:cons](../../hoon/twig/col-cell/hep-cons/)), constructs the 2-element cell
18+[:cons](../../hoon/rune/col/hep/)), constructs the 2-element cell
19that will be our program. The first element, `%say`, tells the
19that will be our program. The first element, `%say`, tells the
20interpreter what to produce--in this case a value.
20interpreter what to produce--in this case a value.
@@ -28,7 +28,7 @@ Similarly, the rest of the program (which we construct with another
28producing a value of type `noun`, and the code that we run to actually
28producing a value of type `noun`, and the code that we run to actually
29produce our value of the type `noun`.
29produce our value of the type `noun`.
31−`=<` ([tisgal](../../hoon/twig/tis-flow/gal-rap/)) is a rune that takes two
31+`=<` ([tisgal](../../hoon/rune/tis/gal/)) is a rune that takes two
32children. The second child is the context against which we run the first
32children. The second child is the context against which we run the first
33child. So in this case, we are running the expression
33child. So in this case, we are running the expression
34`(sum [1.000 2.000])` against everything contained within the `|%`. In
34`(sum [1.000 2.000])` against everything contained within the `|%`. In